You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)
(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)
Answer:
1) (2, 3)
2) (2, -5).
Step-by-step explanation:
2x – y = 1
2x +2y = 10 Subtract to eliminate the 2x:
2x - 2x - y - 2y = 1 - 10
-3y = -9
y = 3.
Plug this into the first equation:
2x - 3 = 1
2x = 4
x = 2.
2)
5x – y =15
x + y = -3 Adding to eliminate y:
5x + x - y + y = 15 + -3
6x = 12
x = 2
Plug this into the first equation:
5(2) - y = 15
-y = 15 - 10 = 5
y = -5.
It's different because they have 2 different numbers<span />
Answer:
x=-7, y=-5. (-7, -5).
Step-by-step explanation:
2y+x=-17
5x-4y=-15
---------------
x=-17-2y
5(-17-2y)-4y=-15
-85-10y-4y=-15
-85-14y=-15
14y=-85-(-15)
14y=-85+15
14y=-70
y=-70/14
y=-5
2(-5)+x=-17
-10+x=-17
x=-17-(-10)
x=-17+10
x=-7
Answer:β (beta).
Step-by-step explanation: