Answer:
It's B for edge 2020
Step-by-step explanation:
Answer: I love among us!
Step-by-step explanation:
The value of this equation is: 4
Answer: 4
The area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
<h3>How to find the area of a trapezoid and rhombus?</h3>
The given pattern consists of rhombus and trapezoids
The formula for calculating the area of rhombus is expressed as:
A = pq/2
Area of trapezoid = 0.5(a+b)h
Given the following
height = 2in
a = 2in
b = 3in
Ara of rhombus = 1(4)/2 = 2 square inches
Area of the trapezoid = 0.5(2+3) * 2
Area of the trapezoid = 5 square inches
Hence the area of the rhombus and trapezoid from the figure are 2 square in and 5 square in respectively
Learn more on area of rhombus and trapezoid here: brainly.com/question/2456096
so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.
the diameter of that circle is 10, so its radius is half that, or 5.
![\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3Dangle~in%5C%5C%20%5Cqquad%20degrees%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%5Ctheta%20%3D180%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%28180%29%28%5Cpi%20%29%285%29%7D%7B180%7D%5Cimplies%20s%3D5%5Cpi%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B%5Cimplies%20s%3D15.7%7D)
