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3 years ago

Simplify 198/726 to the lowest term

1 answer:

3 0

So to simplify fractions, you have to divide the numerator and denominator by their common GCF, or Greatest Common Factor. You would keep going until the numerator and denominator don't have a GCF greater than 1.

$\frac{198}{726} /\frac{6}{6} =\frac{33}{121} \\ \\ \frac{33}{121} /\frac{11}{11} =\frac{3}{11}$

The simplified fraction is 3/11.

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Perimeter of a triangle is 32, sides are x+3, 3x-1 and 4x-2

ZanzabumX [31]

X= 4
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6 0

3 years ago

Write 0.46 as a fraction simplest form

ddd [48]

Answer:23/50

Step-by-step explanation:its 46/100 but it simplifies to 23/50 hope this helps god bless

8 0

3 years ago

Read 2 more answers

Find the unknown value in proportion 2.3/6.7 = 4.6/x a)13.4 b)20.1 c)1.6 d)3.4

Dominik [7]

2.3/6.7 = 4.6/x

using cross products

2.3*x = 6.7 * 4.6

divide by 2.3

x = 6.7 * 4.6 / 2.3

x = 6.7 * 2

x = 13.4

Choice A

5 0

3 years ago

The answer to this question

oee [108]

If the cell phone company charges a flat $40 fee monthly, then the equation would be y = 40.

The company does charge $40 a month, but also charges $2 per minute out of service area (x).

So the equation is y = 2x + 40

To graph this linear function, plug in values for x then plot the plots. Then draw a line to connect the points.

y = f(x)

f(0) = 40
f(1) = 42
f(2) = 44
f(3) = 46
f(4) = 48
f(5) = 50

So at x=0, draw a point at y=40 and so on.

6 0

3 years ago

Mr. Nelson bought a car for $20,000 with a 5% interest rate.

LekaFEV [45]

Answer:

A ) Hence The interest for the car loan is $ 4,310

B ) Hence The interest for the car loan is $ 3,152

Step-by-step explanation:

Given as :

The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

A ) The period of loan = 48 months = 4 years

Let the interest of the loan = CI

From compounded method

Amount = Principal × $(1 + \frac{\textrm Rate}{100})^{\textrm time}$

Or, Amount = $ 20,000 × $(1 + \frac{\textrm 5}{100})^{\textrm 4}$

Or, Amount = $ 20,000 × $(1.05)^{4}$

Or, Amount = $ 20,000 × 1.2155

∴ Amount = $ 24310

So, Interest = Amount - Principal

Or, CI = $ 24,310 - $ 20,000

∴ CI = $ 4,310

Hence The interest for the car loan is $ 4,310

B ) The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

The period of loan = 3 years

Let the interest of the loan = CI

So,

From compounded method

Amount = Principal × $(1 + \frac{\textrm Rate}{100})^{\textrm time}$

Or, Amount = $ 20,000 × $(1 + \frac{\textrm 5}{100})^{\textrm 3}$

Or, Amount = $ 20,000 × $(1.05)^{3}$

Or, Amount = $ 20,000 × 1.1576

∴ Amount = $ 23,152

So, Interest = Amount - Principal

Or, CI = $ 23,152 - $ 20,000

∴ CI = $ 3,152

Hence The interest for the car loan is $ 3,152

6 0

3 years ago