R=11
1 squared is 1
Add ten to one and you get 11!
Answer:
-41
Step-by-step explanation:
The change is -2
(-2*20)-1 = -41
Answer:
0.88
Step-by-step explanation:
You first multiply the fraction by 11 which is 88/99. Then, from common knowledge, you'll know that anything over 99 is repeating itself so it is 0.88 repeating.
For this problem, we have to set up the formula for the equation first. The equation should help us predict how long would it take to reach a life expectancy of 130 years. Let's start by denoting variable to present them in algebraic equations. Let x be the number of decades, while y is the number of years for life expectancy. The base year used here is 2009 with a life expectancy of 80 years. So, we will expect that 80 is a constant in the expression. We will add to this the number of decades multiplied by 5.4, because it stands for 5.4 additional years per decade. When you write this in an equation, it would be
y = 80 + 5.4x
Now, we substitute y=130.
130 = 80 + 5.4x
x = (130 - 80)/5.4
x = 9.259
Therefore, it would take approximately more than 9 decades. Projecting this amount of time from 2009, the year would be:
Projected year = 2009 + 9 decades * (10 years/1 decade)
Projected year = 2101
It would be in year 2101.
Its depends on what you are working on
