Answer:
the last one
maybe?
Step-by-step explanation:
Answer:
<u>Please read the answer below.</u>
Step-by-step explanation:
<u>Question 2. 25% of what number is 30?</u>
25% - Whole 30, 50% Whole 60, 75% Whole 90, 100% Whole 120
<u>Question 3. What operation did you use the find the whole?</u>
In the previous question, I found the whole, adding 30 to the previous value.
For example, I added 30 to 30 and calculate 60. To 60 then i added 30 to get 90 and added 30 to get 120 because in this question, all the 4 parts were exactly the same size (30).
<u>Question 4. What are you multiplying/dividing? Do you use the percent or something else?</u>
In the specific case of question 2, I noticed that the size of the parts were exactly the same, using it for calculating the whole. If 1 part out of 4 is 30, then 2 parts or 50% are 60, 3 parts or 75% are 90 and then 4 parts of 100% are the whole I'm being asked, in this case, 120.
Answer:
Her speed is of 2 miles per hour.
Step-by-step explanation:
Velocity:
The velocity is given by the following formula:
In which v is the velocity, d is the distance and t is the time.
2/3 mile in 1/3 hour .
This means that 
Which unit rate describes antoinettes speed in miles per hour?
This is v. So
Her speed is of 2 miles per hour.
Answer:
Step-by-step explanation:
Part A
This is a combination problem. Order does not matter.
36C6
36!/(30! 6!)
36 * 35 * 34 * 33 * 32 * 31/ 6!
1402410240/6!
1947792
Part B
1 / (36C6)
0.000000513 or
0.0000005
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
