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3 years ago

8

Someone help me please!!!!hurry

2 answers:

MAXImum [283]3 years ago

8 0

Answer:

z = 30; obtuse isosceles triangle

Step-by-step explanation:

4z + z + 30 = 180

5z + 30 = 180

5z (+ 30 - 30) = 180 - 30

5z = 150

5z/5 = 150/5

z = 30

Since z = 30, and 30 = 30, two angles are congruent to each other and there is only one obtuse angle. Therefore, this is an obtuse isosceles triangle.

Digiron [165]3 years ago

4 0

Answer:

30, obtuse isosceles

Step-by-step explanation:

Tow sides are the same making it an isosceles triangle. This requires two of the same sides and two of the same angles. This means that z is the sameas 30 degrees.

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The admission to the fair is $5 and the cost per ride is 50 cents. If his parents give hime $20, write and solve a linear equati

solniwko [45]

Answer:

Step-by-step explanation:

The admission to the fair is $5 and the cost per ride is 50 cents.

Let the number of rides that he can go on be x

If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.

So x rides will cost $0.5x

If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15

The equation to find how many rides he can go on will be

0.5x = 15

Since one ride costs $0.5

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x = 15/0.5 = 30

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8 0

3 years ago

Emma is 10 years old. She asked her father how old he was. Her father answered: "When you will be my age, I will be 70." How old

Svetradugi [14.3K]

Answer:

Emmas father would be 40 years old

Step-by-step explanation:

if the father is 40 years old right now emma will be his age in 30 years.

in 30 years emma will be as old as he was when she was ten (10+30=40)

after the 30 years emmas father who was once 40 years when she asked how old he was would be 70 years old (30+40=70)

4 0

3 years ago

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Using principle of mathematical induction prove that 6^-1 divisble by 5 .

salantis [7]

I suppose the claim is $5 \mid 6^n - 1$ for $n\in\Bbb N$ .

When $n=1$ , we have $6^1 - 1 = 6 - 1 = 5$ , and of course 5 divides 5.

Assume the claim holds for $n=k$ , that $5 \mid 6^k - 1$ . We want to use this to show it holds for $n=k+1$ , that $5 \mid 6^{k+1} - 1$ .

We have

$6^{k+1} - 1 = \left(6^{k+1} - 6\right) + \left(6 - 1) = 6\left(6^k - 1\right) + 5$

Since $5 \mid 6^k - 1$ , we can write $6^k - 1 = 5\ell$ for some integer $\ell$ . Then

$6^{k+1} - 1 = 6\cdot5\ell + 5 = 5(6\ell + 1)$

which is clearly divisible by 5. QED

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2 years ago

3x-8(2x+3)= -6(2x+5)

faust18 [17]

3x-16x-24=-12x-30
-13x+12x=-30+24
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x=6

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3 years ago

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Answer:

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3 years ago

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