If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Easy one....
58
There is no difficult explanation. It’s always the left end of the box and whisker plot.
Answer:
Length = 80 m and breadth = 60 m If one moves along the two adjacent sides, one covers 80+60 = 140 m. Diagonal of the rectangle = √ ( length^2 + breadth^2) ...
Answer:
4 is in the p and 2 in the not p
Step-by-step explanation:
the one with the 40 in p the one with the 12 in p the one with 8 in the p and the one with the 12 with a 3 is in the p the others are in no p.
The picture is upside down my dude, delete the question, re-upload it and ill help you out.
