All categories

3 years ago

What is the smallest part of all matter

Chemistry

2 answers:

Ostrovityanka [42]3 years ago

7 0

An atom is the smallest part of all matter.

Elenna [48]3 years ago

6 0

An atom does not represent the smallest unit of matter...a quark does. Quarks are the building blocks of atoms.

You might be interested in

Hi anyone there who can talk to. me ans this and talk to me in comments

jasenka [17]

Answer:

Do you just want to talk?

Explanation:

Do you need help with anything?

7 0

3 years ago

A decrease in height of a column in a mercury barometer means that

insens350 [35]

Answer:

increase in the air pressure

Explanation:

The barometer is a device that is used for measuring the air pressure. It is a device that uses mercury in order to show the air pressure. The mercury reacts easily to the changes in the air pressure, so it is a nice indicator for it. The air pressure can simply be defined as the weight of the air masses, and the pressure they make it because of it on the objects. The lower the air pressure, the higher up the mercury will go, as it will experience less pressure from the air, and the higher the air pressure, the lower the mercury will drop, as it will experience more pressure from the air.

5 0

3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

B) Radius

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

3 0

3 years ago

11. What is another name for the transition metals? Group B elements noble gases Group A elements Group C elements

finlep [7]

Answer:

Group B elements

Explanation:

Group B metals are referred to as transition metals. They are located in the middle of the periodic table between Group IIA and Group IIIA. They provide transition between the "base formers" on the left and "acid formers" on the right.

3 0

3 years ago

Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.

NARA [144]

PH is the test of acidity or basicity of a solution. it follows the formula:
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case.

By literature, Ka of HF is 3.5*10^-4
pKa= -log(Ka)= 3.46 

pH = pKa + log [NaF / [HF] 

4.05 = 3.46 + log [NaF / [HF]

log [NaF / [HF] = 0.59

[NaF / [HF] = 3.89

4 0

3 years ago

Read 2 more answers