1) k2O = 2K(1+) + O(2-)
This is, every molecule of K2O consists of three ions (2 of K 1+, and one of O 2-)
2) Caluclate the number of moles of K2O
- molar mass of K2O = 2*39 + 16 = 94 g/mol
- n = mass / molar-mass = 9.4g / 94 g/mol = 0.1 mol
3) Multiply by 3 to have the number of moles of ions: 3 *0.1 mol = 0.3 mol of ions.
4) Multiply by Avogadro's number to obtain the number of ions"
0.3 mol * 6.0*10^23 =1.8 * 10^23 ions.
Answer: 1.8*10^23 ions
Yes, it can - HBr is its chemical formula.
If you had other options though, then the one which wouldn't be a valid chemical formula is aluminum (III) chloride, because, since it only has one charge (+3), it is unnecessary to state it as III.
A) mass / volume = density
m/6.00cm3 = 13.5939g/cm3
m = 13.5939g/cm3 • 6.00cm3
m = 81.6g
B) mass / volume = density
m/25.0cm3 = 0.702g/cm3
m = 0.702cm3 • 25.0g/cm3
m = 17.6g
1mL = 1cm3
Technically the answer would be a
