Question

A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal speed of 5.2 m/s toward the front of the cart. What is the final speed of the cart and bag

Answer 1

Answer:

$V=1.77m/s$

Explanation:

#Using the conservation of momentum , momentum before equals momentum after($p=mv)$.

-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.

Hence:

$9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s$

Hence, the final velocity of the cart and bag is 1.77m/s