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Aleks04 [339]
2 years ago
9

A car drives at a velocity of 6.8 m/s for 250 seconds. How far did it travel?

Physics
1 answer:
Leno4ka [110]2 years ago
8 0

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

As we know, Displacement =

\qquad \sf  \dashrightarrow \: velocity  \times time

\qquad \sf  \dashrightarrow \: 6.8 \times 250

\qquad \sf  \dashrightarrow \: 1700 \: m

<h3>OR </h3>

\qquad \sf  \dashrightarrow \: 1.7 \: km

The car travelled 1700 meters ( 1.7 km )

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A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer
dlinn [17]
<h2>Answer:7.14ms^{-1},4.125ms^{-1}</h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let v be the total velocity.

Given that,v=8.25ms^{-1}

We call the horizontal velocity as v_{h} and the vertical velocity as v_{v}.

v_{h}=vCos\alpha

v_{v}=vSin\alpha

where \alpha is the angle between the object and horizontal.

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7 0
3 years ago
a spring gun initially compressed 2cm fires a 0.01kg dart straight up into the air. if the dart reaches a height it 5.5m determi
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Explanation:

Step one

This problem bothers on energy stored in a spring.

Step two

Given data

Compression x= 2cm

To meter = 2/100= 0.02m

Mass m= 0.01kg

Height h= 5.5m

K=?

Let us assume g= 9.81m/s²

Step three

According to the principle of conservation of energy

We know that the the energy stored in a spring is

E= 1/2kx²

1/2kx²= mgh

Making k subject of formula we have

kx²= 2mgh

k= 2mgh/x²

k= (2*0.01*9.81*5.5)/0.02²

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Hence the spring constant k is 2697.75N/m

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For a constant voltage, how is the resistance related to the current?
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Answer:

A

Explanation:

R=V/I

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2R=(1/2)I

8 0
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