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ella [17]
3 years ago
7

I really don't understand.

Mathematics
2 answers:
sleet_krkn [62]3 years ago
7 0
The answer is y = -5
MA_775_DIABLO [31]3 years ago
4 0
6y-74=4(2y-11+y)
6y-74=8y-44+4y
6y-74=12y-44
6y=-30
Y=-5
The correct answer is y=-5
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In a right triangle sin(40+x)=cos(4x)<br> what is the value of x?
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Answer:

Thx for the points

Step-by-step explanation:

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3 years ago
WHAT IS THE SOLUTION TO 5-2N= 17
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N is equal to 11 because 5-2n=17 would be changed into 2n-5=17 because it would be -17 if it was the original problem so that is why 

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Read 2 more answers
Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

y = 38 - 32 = 6

32 five-dollar bills and 6 ten-dollar bills

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3 years ago
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Reil [10]
The napkin explains for itself

5 0
4 years ago
Jesse drank 3/4 of liter of water Monday before going jogging. He drank 3/5 of a liter of water after his jog. How much water di
charle [14.2K]

Answer:

1\frac{7}{20}

Step-by-step explanation:

Step one

Given data

On  Monday, Jesse drank 3/4 of liter of water before jogging

and drank 3/5 of liter after jogging

In all, Jesse drank 3/4 and 3/5 liters of water

= 3/4+3/5

the lcm is 20

=15+12/20

=27/20

in mixed numbers(i.e a whole and a fraction together we have) we have

1\frac{7}{20}

8 0
3 years ago
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