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3 years ago

5 positive integers must have the following:

1 answer:

7 0

A mode of 10 means that at least two of the four numbers are 10 (if the other two aren’t also the same, and given that there is no reason to assume that the set has two modes, we will not assume so). So two of the numbers are 10.

The median is eight. Given that there are four numbers in the set, that means that 8 is the average of the two middle numbers. Given that 10 is obviously higher than the median, the third and fourth numbers (when ranked in ascending order) are the two 10′s. The two middle numbers - 10 is one of them - should add up to 16 to produce a median of 8. 6 must be another number in the set.

Finally, knowing that the range is 5, and the largest number is 10, the final number in the set must be 5.

The set of four numbers is thus {5, 6, 10, 10}.

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saw5 [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

What is 10/15 = N/96

Snezhnost [94]

Answer:

n = 64

Step-by-step explanation:

We can solve using cross products

10/15 = n/96

10*96 = 15*n

960 = 15n

Divide each side by 15

960/15 =15n/15

64 = n

6 0

3 years ago

Read 2 more answers

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago

Hazel has band practice every other day and volunteers every seven days. if she had a band practice and volunteered on oct 23, w

LuckyWell [14K]

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3 0

3 years ago

What is the ratio for 8 and 12

Vitek1552 [10]

It can be 8:12 or as a fraction it’s 8/12

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3 years ago