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Tju [1.3M]
3 years ago
10

Nina bought four pieces of candy. She paid for it with a 10 dollar bill. Let ‘c’ represent the cost of one piece of candy. Pick

the expression that represents the total amount of money she has leftover.
THE ONLY ANSWERS
4c + 10
10c - 4
4 + 10c
10 - 4c
Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

It should be the last one, 10 - 4c.

Step-by-step explanation:

Because base on the problem it should be a subtraction problem. "C" is the pieces of candy so it would be 4c. Your finding the amount left, so 10 - 4c is the answer.

Answer: 10 - 4c

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Let p be the proposition: Triangle ABC is a right triangle with m(C)=90°.

Let q be the proposition: The sides of triangle ABC are such that 

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An example of a conditional statement is : p⇒q, that is:

if Triangle ABC is a right triangle with m(C)=90° then The sides of triangle ABC are such that |AB|^2=|BC|^2+|AC|^2


This compound proposition (compound because we formed it using 2 other propositions) is true. So the truth value is True, 


the converse, inverse and contrapositive of p⇒q are defined as follows:

converse: q⇒p
inverse: ¬p⇒¬q (if [not p] then [not q])
contrapositive: ¬q⇒¬p

Converse of our statement:

if The sides of triangle ABC are such that |AB|^2=|BC|^2+|AC|^2
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Inverse of the statement:

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Contrapositive statement:

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4 0
4 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1406 referee​ calls, with the re
erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

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The null hypothesis is

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The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

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n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

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From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

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