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exis [7]
2 years ago
5

Which is the standard form of y-3=2(x-4) (A) Y=-2x-5 (B)2x-5 (C)2x+y=-5 (D)2x-y=5

Mathematics
1 answer:
pantera1 [17]2 years ago
4 0

y -3 = 2(x-4)

Use distributive property on the right side:

y - 3 = 2x -8

Add 3 to both sides:

y = 2x -5

The answer is A.

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A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
Ira Lisetskai [31]

The length of the rectangle is = 72 cm

The width of the rectangle is = 56 cm

Area of the rectangle is = length*width

= 72\times56=4032 cm²

As given, the other rectangle has the same area as this one, but its width is 21 cm.

Let the length here be = x

4032=x*21

x=\frac{4032}{21}=192

Hence, length is 192 cm.

We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.

So, in the new rectangle,constant of variation=k is given by,

\frac{192}{72}=\frac{8}{3} or \frac{56}{21}=\frac{8}{3}

Hence, the constant of variation is \frac{8}{3}

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2 years ago
2990000 divided by 56276
marta [7]

Answer:

I'm sorry, I think you mistyped, but the answer for this is 53.130997227947970715758049612623

Have a nice day! :)

-Vana

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3 years ago
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Samantha bought a package of 6 pens for $4.32. How much would 2 pens cost. Write your answer in dollars and cents.
lubasha [3.4K]

Answer:

$1.44

Step-by-step explanation:

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Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).
andre [41]
Check the picture below.  So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{{{ a }}^2+{{ b }}^2}
\end{cases}\\\\
-------------------------------\\\\

\bf \begin{cases}
h=0\\
k=0\\
a=4\\
c=5
\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1
\\\\\\
c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{5^2-4^2}=b\implies \boxed{3=b}
\\\\\\
\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}

7 0
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What is .363636 as a fraction
Kay [80]
.363636 as a fraction is 4/11
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