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4 years ago

2SO(g) <-> 2SO2(g) + O2(g)

Chemistry

1 answer:

Rama09 [41]4 years ago

3 0

The correct reaction is:

2SO₃(g) ⇄ 2SO₂(g) + O₂(g)

Answer:

Explanation:

The equilibrium is reached when the velocity of the formation of products is equal to the velocity of the formation of the reactants, and it's can be represented by the constant of equilibrium Keq, which depends on the temperature.

For a generic reaction:

aA + bB ⇄ cC + dD Keq = $\frac{[C]^c*[D]^d}{[A]^a*[B]^b}$

Then, for the reaction given,

Keq = ([O₂]*[SO₂]²)/[SO₃]²

When more O₂ is injected into the reaction, the equilibrium is disturbed, and to solve this, the O₂ must be consumed. So, the amount of SO₂ will be reduced, the amount of SO₃ will be increased, and the value of Keq must remain constant because there's no change in the temperature.

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Which rigid cylinder contains the same number of gas molecules at STP as a 2.0-liter rigid cylinder containing H2(g) at STP?

Inga [223]

When we say STP that means the system is at its standard temperature and pressure. Both systems is having the same condition hence temperature and pressure is constant. We then set the amount of gas in both cases to be equal. Hence from the ideal gas law,
PV=nRT we can say that with everything constant, volume must also be constant.

The answer is (2) 2 L of methane gas.

4 0

3 years ago

Tim and Jim finished their lab experiment earlier than their classmates. What should they do while they wait for the others to f

Alisiya [41]

The answer to your question is,

C. Look over their answers to the lab questions and check for errors.

-Mabel <3

3 0

4 years ago

03/08/2020

Tanzania [10]

Explanation:

According to your question, 

no. a. ans would be like; chemical formula is defined as the an expression which determines no. and type of molecule of a compound. 

b. no. ans; it tells that what type of compound is formed with the type and no. of atoms present in the atom.

c. no ans; the formulation of h2so4 states that it is acid named as hydrochloric acid which is formed by reacting of hydrogen (2 atoms ) ,sulpher (*1atom) and oxygen(4atoms).

Hope it helps...

8 0

3 years ago

Please help it’s due today I will give brainliest

Thepotemich [5.8K]

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0

3 years ago

Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits and put the units.

marta [7]

Answer:

Approximately $53.3\; \rm g$ .

Explanation:

Lookup Avogadro's Number: $N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}$ (three significant figures.)

Lookup the relative atomic mass of $\rm H$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm H$ : $1.008$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

(For example, the relative atomic mass of $\rm H$ is $1.008$ means that the mass of one mole of $\rm H\!$ atoms would be approximately $1.008\!$ grams on average.)

The question counted the number of $\rm H_2SO_4$ molecules without using any unit. Avogadro's Number $N_{\rm A}$ helps convert the unit of that count to moles.

Each mole of $\rm H_2SO_4$ molecules includes exactly $(1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}$ of these $\rm H_2SO_4 \!$ molecules.

$3.27 \times 10^{23}$ $\rm H_2SO_4$ molecules would correspond to $\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol$ of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of $\rm H_2SO_4$ gives the mass of each mole of $\rm H_2SO_4\!$ molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

$\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the mass of approximately $0.541389\; \rm mol$ of $\rm H_2SO_4$ :

$\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}$ .

(Rounded to three significant figures.)

6 0

3 years ago