Question

2SO(g) <-> 2SO2(g) + O2(g)

Answer 1

The correct reaction is:

2SO₃(g) ⇄ 2SO₂(g) + O₂(g)

Answer:

D.

Explanation:

The equilibrium is reached when the velocity of the formation of products is equal to the velocity of the formation of the reactants, and it's can be represented by the constant of equilibrium Keq, which depends on the temperature.

For a generic reaction:

aA + bB ⇄ cC + dD Keq = $\frac{[C]^c*[D]^d}{[A]^a*[B]^b}$

Then, for the reaction given,

Keq = ([O₂]*[SO₂]²)/[SO₃]²

When more O₂ is injected into the reaction, the equilibrium is disturbed, and to solve this, the O₂ must be consumed. So, the amount of SO₂ will be reduced, the amount of SO₃ will be increased, and the value of Keq must remain constant because there's no change in the temperature.