Answer:
The answer is
<h2>25 mL</h2>Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of CCl4 = 40g
Density = 1.6 g/mL
The volume is
We have the final answer as
<h3>25 mL</h3>Hope this helps you
<u>Answer:</u> The total volume of the gaseous products is 1044.29 L
<u>Explanation:</u>
We are given:
Volume of butane = 116 L
At STP:
22.4 L of volume is occupied by 1 mole of a gas
So, 116 L of volume will be occupied by = of butane
The chemical equation for the combustion of butane follows:
By Stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide
So, 5.18 moles of butane will produce = of carbon dioxide
Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L
By Stoichiometry of the reaction:
2 moles of butane produces 10 moles of water vapor
So, 5.18 moles of butane will produce = of water vapor
Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L
Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L
Hence, the total volume of the gaseous products is 1044.29 L