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Maru [420]
3 years ago
10

Please help it’s due today I will give brainliest

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
7 0

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

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[Send a message] as you move across a row from left to right in the period table, atomic numbers of the elements
SashulF [63]
I think it might be D or B 
And my other two might be A or C 
6 0
4 years ago
One atom of silicon can properly be combined in a compound with
julia-pushkina [17]

Answer:

C. two atoms of oxygen.

Explanation:

Step 1: Data given

Silicon has 14 electrons

Silicon is part of Group IV, all the elements there have 4 valence electrons.

It can form a compound when 4 valence electrons bind with the 4 valence elctrons of silicon

A. four atoms of calcium.

Calcium has 2 valence elctrons. 4 atoms of calcium <u>cannot bind</u> on 1 atom of silicon since there are only 4 valence electrons.

B. one atom of chlorine.

1 atom of chlorine has 7 valence electrons. Chlorine can bind with an atom with 1 valence electron. Since silicon has 4 valence electrons, they will <u>not bind.</u>

Silicon can bind with 4 atoms of chlorine to form SiCl4

C. two atoms of oxygen.

Oxygen has 6 valence electrons, this means oxygen can bind with an element with 2 valence electrons.

Since silicon has 4 valence electrons, it <u>can bind</u> with 2 atoms of oxygen to form SiO2 (silicon dioxide).

D. three atoms of hydrogen.

Hydrogen has 1 valence electron. 1 hydrogen atom can bind with an element that has 7 valence electrons.

Three atoms of hydrogen can bind with an element that has 5 valence electrons.

Silicon <u>will not</u> bind with 3 atoms of hydrogen ( but can bind with 4 atoms of hydrogen)

5 0
4 years ago
Please help ASAP<br> Will give brainliest
Leni [432]

Answer:  457.8

Explanation:

345.8*225/703.55

8 0
3 years ago
What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?
tiny-mole [99]

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

4/58.45=ans./3.8=.018 M

8 0
3 years ago
Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical
melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

  1. C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
  2. H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
  3. 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0
3 years ago
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