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3 years ago

10

Please help it’s due today I will give brainliest

1 answer:

Thepotemich [5.8K]3 years ago

7 0

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

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12345 [234]

Answer) All of the above

7 0

3 years ago

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Select the electron-domain geometry for a molecule with three bonding domains and one nonbonding domain.

mamaluj [8]

Answer: C) Tetrahedral

Explanation:

The number of electron pairs is 4 that means the hybridization will be $sp^3$ but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be $sp^2$ .

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be $sp^3$ .

Trigonal bipyramidal geometry is possible when number of electron pairs is 5 and the hybridization will be $sp^3d$ .

Octahedral geometry is possible when number of electron pairs is 6 and the hybridization will be $sp^3d^2$ .

6 0

3 years ago

WILL GIVE BRAINLIEST, Which of the following would have the greatest amount of surface area?

Elodia [21]

Answer:

C. 1 cubic foot of loose sand

Explanation:

For many objects having equal volume , surface area will be maximum

of the object which has spherical shape .

But when a sphere is broken into tiny small spheres , total surface area of all the small spheres will be more than surface area of big sphere .

Hence among the given option , surface area of loose sand will have greatest surface area . Loose sand is equivalent to small spheres .

5 0

3 years ago

Rubidium is in Group I of the Periodic Table and bromine is in Group VII.

tensa zangetsu [6.8K]

The answer to this question would be C

7 0

3 years ago

svet-max [94.6K]

No of protons=No of electrons=15

<h3>Mass no:-No of neutrons+No of protons </h3>

$\\ \tt\longmapsto 15+16=31$

Now

It has atomic no 15 hence its Phosphorus(P)

Electronic configuration:-

$\\ \tt\longmapsto 1s^22s^22p^63s^23p^3$ .

Valency=3

Chloride formula:-

$\\ \tt\longmapsto XCl_3$

or.

$\\ \tt\longmapsto PCl_3$

5 0

3 years ago

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