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tester [92]
3 years ago
5

Tim and Jim finished their lab experiment earlier than their classmates. What should they do while they wait for the others to f

inish?
A.
look for an interesting experiment in their lab manual and perform that experiment
B.
grab a snack out of their backpacks and eat it in the lab area
C.
look over their answers to the lab questions and check for errors
D.
bring their math textbooks to the lab area and finish tonight's homework
Chemistry
1 answer:
Alisiya [41]3 years ago
3 0

The answer to your question is,

C. Look over their answers to the lab questions and check for errors.

-Mabel <3

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What can you tell about a solution by using a phenolphthalein solution?
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Answer:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions. ... It is a weak acid, which can lose H+ ions in solution.

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A water sample tested positive for lead with a concentration of 35 ppm. The density of the solution is 1.00 g/mL Which of the fo
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Answer: option B. there are 35 mg of lead in 1.0 L of this solution

Explanation:

1ppm = 1mg/L

Therefore 35ppm = 35mg/L

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3 years ago
Help meeee!<br> 3874 dkg = _____ dg
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Which diagram shows the correct electron configuration for fluorine (F)?
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it's A

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6 0
2 years ago
Read 2 more answers
Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot
Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = p_1=0.20 atm

Partial pressure of the helium = p_2

p_1=p\times \chi_1 (Dalton law of partial pressure)

0.20 atm=4.42 atm\times \chi_1

\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525

\chi_2=1-\chi_1=1-0.04525=0.95475

chi_1+chi_2=1

n_1=0.04525 mol,n_2=0.95475 mol

According Avogadro law:

Moles\propto Volume (At temperature and pressure)

Volume occupied by oxygen gas  =V_1

Total moles of gases = n = 1 mol

Total Volume of the gases = V

\frac{n_1}{V_1}=\frac{n}{V}

\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}

Percent by volume of oxygen in the gas mixture:

\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%

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4 years ago
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