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aksik [14]
3 years ago
11

10. Based on their valence electrons, how many

Chemistry
1 answer:
Kaylis [27]3 years ago
4 0

will share 2 elctrons with 2 Cl to form

S in column 16 WILL SHARE 2 ELECTRONS WITH 2 /Cl to form

SCl2

,

Answer:

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Explanation:

10. Based on their valence electrons, how many

atoms of chlorine are expected to bond

with each of the following elements?

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Cl is in Periodic Table column 17, so it has 7 valence  and needs 1 more to have an electronic structure like its nearest noble gas, Ar.

It then has an oxidation state 0f -1.

Carbon in column  has  +/-4 charge, so 4 Cl will bond with 1 C to make

covalent CCl4

Nitrogen in column 15  is -3.  It will share 3 electrons with 3 Cl to form

covalent NCl3

Al in column 13 give away 3 electrons to 3 Cl to form

ionic AlCl3

S in column 16 will share 2 electrons with 2 Cl and frorm

SCl2

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3<br> Write the alpha decay WITH gamma emission for the following element:<br> 92<br> AL<br> 27
erma4kov [3.2K]

Answer:

Explanation:

In alpha decay alpha ray comes out . Apha ray is nothing but nucleus of helium atom whose atomic no  is 2 and atomic weight is 4 . Hence in alpha decay , atomic weight reduces by 4 and atomic no reduces by 2. For gamma emission , there is no change in atomic number and atomic mass.

⁹²₂₇AL ⇒ ⁸⁸₂₅X + ⁴₂He + γ

X is Manganese .

4 0
3 years ago
A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
erica [24]

Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

Best regards!

4 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
4 years ago
The area that includes everything between the cell membrane and the nucleus of a cell is called the
kolbaska11 [484]

Answer:

Cytoplasm.

Explanation:

Please mark as Brainliest! :)

8 0
3 years ago
Read 2 more answers
The ground state of an electron is the least stable energy state of an atom
kari74 [83]

Answer:

electron configuration

Explanation:

The arrangement of electrons in the atomic orbitals of an atom is called the electron configuration. Electron configurations can be determined using a periodic table.

6 0
3 years ago
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