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3 years ago

Which of the following is a logarithmic function?

Mathematics

2 answers:

g100num [7]3 years ago

7 0

the answer is not A

i think it B

Ipatiy [6.2K]3 years ago

3 0

Only a function that actually shows the word "ln" or "log" or "log to the base b" is a log function.

Taking a closer look at #3: y = log 0.25^x, we see that this can be simplified by writing the base (10) as follows: 10 10

and then using y as the exponent of the first 10 and log 0.25^x as the exponent of the second 10:

10^y = 10^(log 0.25^x)

You were not asked to do this, but this discussion may be of interest and help to you down the line.

10^y = 0.25^x

You might be interested in

If 6t-3=-177 what is the value of the variable

stealth61 [152]

Add 3 to -3 and -177 then divide -174 by6

6 0

3 years ago

Read 2 more answers

18. Jackie drives 160 miles from Gary, Indiana to

astra-53 [7]

Answer:

11 hours and 15 minutes (11.25)

Step-by-step explanation:

make a ratio

160:4.5

240/160=1.5

so 1 and 1/2 intervals of 4.5 hours

4.5+4.5= 9

4.5/2=2.25

9+2.25=11.25

6 0

3 years ago

Enter the domain and range of the function g(x) = 9x2 − 5 as an inequality, using set notation and using interval notation. Comp

tia_tia [17]

The domain and the range of a function are the set of input and output values, the function can take.

The domain and the range of $g(x) = 9x^2 - 2$ is $(-\infty, \infty)$ .
The parent function $f(x) =x^2$ is vertically compressed by 9, then shifted down by 5 units to get $g(x) = 9x^2 - 2$

Given

$g(x) = 9x^2 - 2$

Domain and range

There is no restriction as to the input and the output of function g(x).

This means that the domain and the range are $(-\infty, \infty)$

$(-\infty, \infty)$ is in interval notation

The corresponding set notation is: $- \infty < x < \infty$

The parent function

We have:

$f(x) = x^2$

First, the parent function is vertically compressed by a factor of 9.

The rule of this transformation is:

$(x,y) \to (x,9y)$

So, we have:

$f'(x) = 9x^2$

Next, the function is shifted down by 5 units.

So, we have:

$g(x) = f'(x) - 5$

$g(x) = 9x^2 - 5$