Answer:
The y-coordinate of their intersection point is 3
That is y=3
Step-by-step explanation:
Given two lines are y=6x+15 and y=mx+4
Given that the two lines intersect at x=-2
To find the y coordinate of their intersection point :
Equating the two lines
6x+15=mx+4
6x+15-mx-4=0
6x-mx+11=0
(6-m)x+11=0
At x=-2 (6-m)x+11=0
(6-m)(-2)+11=0
(6-m)(-2)=-11





Substitute the value
in y=mx+4 we get

At x=-2 


Therefore y=3
Therefore the y-coordinate of their intersection point is 3
Answer:
a.27
Step-by-step explanation:
Using Pythagoras theorem:
x=sqrt(6^2+26^2)
x=26.683..
By rounding, x=27
Answer:
x = 53.6588°
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] cos∅ = adjacent over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use trig to find the missing angle.
<u>Step 2: Identify Variables</u>
<em>POV from angle x</em>
Angle = <em>x</em>
Adjacent = 16
Hypotenuse = 27
<u>Step 3: Solve for </u><em><u>x</u></em>
- Substitute: cosx° = 16/27
- Inverse: x° = cos⁻¹(16/27)
- Evaluate: x = 53.6588°
The answer would be 26 due to the fact that it’s just nearly above the 25 mark