Answer:
The lateral area is 624 unit²
Step-by-step explanation:
* Lets explain how to solve the problem
- The regular square pyramid has a square base and four congruent
triangles
- The slant height of it =
, where
b is the length of its base and h is the perpendicular height
- Its lateral area =
, p is the perimeter of the base
and l is the slant height
* Lets solve the problem
∵ The base of the pyramid is a square with side length 24 units
∵ Its perpendicular height is 5 units
∵ The slant height (l) = 
∴ l = The slant height of it = 
∴ l = 
∴ l = 13 units
∵ Perimeter of the square = b × 4
∴ The perimeter of the base (p) = 24 × 4 = 96 units
∵ The lateral area = 
∴ The lateral area = 
∴ The lateral area = 624 unit²
* The lateral area is 624 unit²