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storchak [24]
3 years ago
5

Estimate $0.89 ×14 find each product

Mathematics
1 answer:
viva [34]3 years ago
5 0
The product of $0.89 x 14 equals 12.46
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To get to school you can travel by car, bus or bicycle. If you travel by car, there is a 50% chance you will be late because the
Irina18 [472]

Answer:

a) 16.66%

b) 5%

Step-by-step explanation:

a)

Since the teacher assumes each of the three possibilities are equally likely, then he assumes 33.33% to each one.

In this case the probability that you traveled to school that day by car would be

50%  of 33.33% = (0.5)(0.3333) = 0.1666 = 16.66%

b)

In this case, the teacher would assume

90% ride on bicycle

0% take the bus

10% travel by car

So, in this case the probability would be

50% of 10% = (0.5)(0.1) = 0.05 = 5%

6 0
3 years ago
Can 57 rows be divided into equal sections
Serjik [45]
Yes it can be divided into 3 equal sections of 19
8 0
3 years ago
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The perimeter of a rectangular garden is 24. If the length is half the width, what is<br> the width?
Anna11 [10]

Let length be x

  • Width be 2x

ATQ

\\ \sf\longmapsto 2(L+B)=24

\\ \sf\longmapsto 2(x+2x)=2=

\\ \sf\longmapsto 2(3x)=24

\\ \sf\longmapsto 6x=24

\\ \sf\longmapsto x=\dfrac{24}{6}

\\ \sf\longmapsto x=4

4 0
3 years ago
Read 2 more answers
Please help, please help
zmey [24]
Answers:
x=22
x+4=26
6x=132

Explanation:
We learned from the question that all of the angles in a triangle add up to 180 degrees.

180=angle+angle+angle

When we plug in the values that the question gives us for the angles, we get this equation:

180=x+6x+(x+4)

After solving this equation, we get 22 as the value of x (The process of solving that equation is in the picture attached).

To solve for (x+4), we plug in the value of x, which is 22 and add 4.

(x+4)
=(22+4)
=26

And finally, to solve for 6x, we plug in 22 again:

6x
=6*22
=132

Hope this helps!

7 0
3 years ago
To prove ABC= ADC, To prove which triangle postulate could you use?
Kay [80]

Answer:

ASA

Step-by-step explanation:

..................

6 0
3 years ago
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