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tatiyna
3 years ago
5

The sum of the terms of a sequence 1+ 3 + 5 + 7 + 9

Mathematics
2 answers:
Serggg [28]3 years ago
6 0

Answer:

25

Step-by-step explanation:

1 + 3 + 5 +7 +9

1+3 = 4

4+5 + 7 +9

4+5=9

9 + 7 +9

9+7 = 16

16 + 9 = 25

Ps: You can just search online

ExtremeBDS [4]3 years ago
3 0

Answer:

if you add it all up it is  25

Step-by-step explanation:

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Alex paid $20,448 for a new car. He will make equal payments each month or 4 years. What will be Alex's monthly car payment
fgiga [73]

Answer:

$426

Step-by-step explanation:

According to the question,

New car cost = $20,448

Time to repay = 4 years or 48 months

So, we can calculate the monthly car payment by using following formula,

Monthly car payment = New car cost ÷ Time to repay

By putting the value, we get

Monthly car payment = $20,448 ÷ 48

= $426

Hence, Alex monthly car payment is $426.

5 0
3 years ago
Please help me in this question please
4vir4ik [10]

Answer:

The first one and the second one

Step-by-step explanation:

6 0
3 years ago
Drag the measurements to the containers to show equal length.
Pani-rosa [81]

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

1 ft = 12 in; 1 yd = 3 ft and 1 yd = 36 in.

Hence:

15 yd = 15 yd * 36 in per yd = 540 in

195 ft = 195 ft * 12 in per ft = 2340 in

5280 yd = 5280 yd * 3 ft per yd = 15840 ft

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

Find out more on equation at: brainly.com/question/2972832

3 0
2 years ago
What is 22 1/6+ 10 4/5
LUCKY_DIMON [66]
32 29/30 its 32 and 5/30+24/30
3 0
3 years ago
Read 2 more answers
Para embalar una caja se emplea 4,2 m de cinta adhesiva. ?Cuántas cajas se podrán embalar con tres rollos que tienen 3 hm, 7 dam
kompoz [17]

For this case, we perform the conversions:

First roll:

1 \ Hectometer --------> 100 \ meters\\3 \ Hectometer --------> x

x = \frac {3 * 100} {1}\\x = 300 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 300 meters of adhesive tape.

1 -----------> 4.2

c -----------> 300

c = \frac {300 * 1} {4.2}\\c = 71.42857143\\c = 71

You can pack 71 boxes.

Second roll:

1 \ Decametro --------> 10 \ meters\\7 \ Decameter --------> x\\x = \frac {7 * 10} {1}\\x = 70 \ meters.

We make a rule of three to determine the number of "c" boxes that can be packed with 70 meters of adhesive tape.

1 -----------> 4.2

c -----------> 70

c = \frac {70 * 1} {4.2}\\c = 16.66666667\\c = 16

You can pack 16 boxes.

Third roll:

1 -----------> 4.2

c -----------> 50

c = \frac {50 * 1} {4.2}\\c = 11.9047619\\c = 11

You can pack 11 boxes.

Thus, in total you can pack11 + 16 + 71 = 98 \ boxes

Answer:

98 boxes

4 0
3 years ago
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