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kupik [55]
3 years ago
15

While mRNA strands are being created, a sequence is sometimes miscopied. What is the worst that could happen to a cell should th

is take place?
Biology
2 answers:
sashaice [31]3 years ago
6 0

Answer:

The question lacks options, the options are:

A) The cell will not make functional proteins from that mRNA strand

B) The cell will die once it tries to use that strand of mRNA

C) The cell will have to destroy any ribosomes that use the mRNA strand

D)The cell will pass the mRNA on to all the cells made from it.

The correct answer is A

Explanation:

During protein synthesis, the cell initially undergoes transcription in which a complementary strand of mRNA is produced using a DNA template. This process is carried out by the RNA polymerase enzyme by copying nucleotide bases on the growing RNA, complementary to the ones on DNA. The information on the mRNA is in form of nucleotide base sequences which are read in a group of three nucleotides called CODON, which specifies a particular amino acid that makes up functional proteins. If a sequence of these bases is miscopied, it will lead to MUTATION.

Mutation is any change (small or large) in the nucleotide sequence in the genome. It can occur due to mistakes during copying as is the case here. The mutation can occur in such a way that nucleotide bases will be deleted, inserted, or substituted. In some of these mutations, the effect can be beneficial or harmful in others.

However, since the genetic code consists of specific order of bases in mRNA that specifies a specific order of amino acids in a protein, a change in any of the sequences (mutation) will at worst result in the cell's inability to make functional proteins using the affected mRNA strand.

The nucleotide sequence in the mRNA will be altered, which will ultimately alter the amino acid sequence resulting in the production of dysfunctional proteins.

mote1985 [20]3 years ago
4 0
When an error occurs that leads to mutations
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maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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