It's kind of a mix between A and C there are some defragmenting tools that show you how much of your PC is wasted by program files. And in some defragmenting tools, it shows you all the files that are fragmented and gives you the option to defrag them or not. So the best answer would be A.
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
#include <stdio.h>
struct student {
char firstName[50];
int roll;
float marks;
} s[5];
int main() {
int i;
printf("Enter information of students:\n");
// storing information
for (i = 0; i < 5; ++i) {
s[i].roll = i + 1;
printf("\nFor roll number%d,\n", s[i].roll);
printf("Enter first name: ");
scanf("%s", s[i].firstName);
printf("Enter marks: ");
scanf("%f", &s[i].marks);
}
printf("Displaying Information:\n\n");
// displaying information
for (i = 0; i < 5; ++i) {
printf("\nRoll number: %d\n", i + 1);
printf("First name: ");
puts(s[i].firstName);
printf("Marks: %.1f", s[i].marks);
printf("\n");
}
return 0;
}
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