Answer:
20
Step-by-step explanation:
Answer:
∠F = 42° to the nearest degree
Step-by-step explanation:
In this question, we are asked to calculate the value of the angle.
Kindly note that since one of the angles we are dealing with in the triangle is 90°, this means that the triangle is a right-angled triangle
Please check attachment for the diagrammatic representation of the triangle
From the diagram, we can identify that the EF is the hypotenuse and the length FG is the adjacent. Thus , the appropriate trigonometric identity to use is the cosine
mathematically;
Cosine of an angle = length of adjacent/length of hypotenuse

F = 42.07
∠F = 42° to the nearest degree
Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Just fill in the problem... 3*-2-1-3*-2
If the angle in B is 45º, that means the angle in A is also going to be 45º, considering it's a right triangle, so AC and BC are they have the same length.
Then using Pythagoras, you'll get that

equals

.
Now, you know that AC=BC and that AB=24.
So you'll get

. You do the square root in both sides and you get that 2AC=24 and AC=12.
Now that you know that both AC and BC equal 12, you can find the area by just multiplying them and then diving them by 2. (The formula for the area of a triangle is half base multiplied by height, and in a right triangle, if a cathetus is the base, the other cathetus<span> will be the height)
And so the area is equal to 72.</span>