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juin [17]
3 years ago
9

83 POINTS FOR WHOEVER ANSWERS THESE QUESTIONS: PICTURES

Mathematics
2 answers:
motikmotik3 years ago
7 0

Answer:

y=sqrt((x+a)/-2b))

F=(5/9)C+32

Can't read the rest

Step-by-step explanation:

-2by^2=x+a

y^2=(x+a)/-2b

y=sqrt((x+a)/-2b))


F-32=(5/9)C

F=(5/9)C+32 (The actual Fahrenheit-Celcius formula)

NOTE: The other pictures cannot be opened.



Rus_ich [418]3 years ago
7 0

Hi there! Im going to answer the subject of the formula x=a-2b^2

To find you need  to subtract the a to the negative 2 which is going to be -1

So the actual Fahrenheit-Celcius formula is F=(5/9)C+32

Hope this helps

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Evaluate:<br> <img src="https://tex.z-dn.net/?f=32%5E%7B-%20%5Cfrac%7B2%7D%7B5%7D%20%7D%20%3Cbr%3E%3Cbr%3E%3Cbr%3E%3Cbr%3E%3Cbr%
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32^{- \frac{2}{5} }  =  ( \frac{1}{32}) ^{ \frac{2}{5} } = ( \frac{1}{32} )^{ \frac{1}{5} *2}  =  [ ( \frac{1}{32}) ^{ \frac{1}{5} } ]^{2}  =  ( \sqrt[5]{ \frac{1}{32} } ) ^{2}  =  ( \sqrt[5]{ \frac{1}{2}*  \frac{1}{2} *  \frac{1}{2} *  \frac{1}{2} *  \frac{1}{2}   } )^{2} = ( \frac{1}{2} )^{2}   answer 

<span>the notebook
</span>(32)^{-  \frac{2}{5} }  =  ( \sqrt[5]{ \frac{1}{32} } )^{2}  = ( \frac{1}{2}  )^{2} =  \frac{1}{4}<span>

</span>
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3 years ago
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