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3 years ago

Find the LCM of 5 and 12

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

7 0

Answer:

it's 60

Step-by-step explanation: please brainliest?

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Y = 2x + 3 find the 151st term

harkovskaia [24]

Y=2(151)+3

y=302+3

y=305

So the 151st term is 305

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3 years ago

Find the 9th term geometric sequence 1,1/2,1/2^2

valentinak56 [21]

Answer: $t_9=\dfrac{1}{2^8}$

<u>Step-by-step explanation:</u>

$t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}$

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3 years ago

Simplify (√3 − √7)^2

Alika [10]

Answer: 10 - 2√21

Step-by-step explanation: I simplified your question by using an online calculator. :)

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3 years ago

Can anyone help me with this problem?

Mrac [35]

Answer: The number of tomatoes went up relative to the increase of fertilizer used. the slope is positive.

Step-by-step explanation:

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4 years ago

Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S

Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = $\sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}$

AC = $\sqrt{(2-4)^2+(1-1)^2} =2$

BC = $\sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}$

For triangle SRT we have

RS = $\sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}$

RT = $\sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2$

ST = $\sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}$

Therefore their dimensions are equal

However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0

4 years ago

Read 2 more answers