F(x) = 3x^2-3x + 1 Find f (-2)

Mathematics

1 answer:

Oxana [17]4 years ago

8 0

Answer:

Step-by-step explanation:

f(x) = 3x^2-3x + 1

Let x = -2

f(-2) = 3( -2)^2-3*-2 + 1

= 3 * 4+6+1

= 12 +6+1

= 19

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Find an equation of the line that satisfies the given conditions.

8090 [49]

Answer:

$x=8$

Step-by-step explanation:

Given:

The equation of the given line is $y=9$

A point on the unknown line is (8, 5).

The unknown line is perpendicular to the line $y=9$ .

A line of the form $y=a$ where 'a' is a constant is a line parallel to the x axis. The line has a constant value for 'y' irrespective of the value of 'x'. The slope of such lines are equal to 0. So, slope of the known line is 0.

Now, when two lines are perpendicular, the product of their slopes is -1.

Let the slope of the unknown line be 'm', then:

$m\times 0 =-1\\m=-\frac{-1}{0}=$ undefined.

Therefore, the slope of the unknown line is undefined. A line parallel to y axis has undefined slope. So, the equation of the unknown line is of the form:

$x=b$ where, 'b' is a constant and is equal to the abscissa (x value) of the line.