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Leona [35]
2 years ago
8

Which expression is equivalent to

Mathematics
1 answer:
Tasya [4]2 years ago
3 0

Answer:

1/x^24

Step-by-step explanation:

(x^-6/x^2)^3 multiply the powers inside the parenthesis by power outside of the parenthesis to get rid of parenthesis

x^-6×3/x^2×3 = x^-18/x^6

subtract the denominator's power from nominator's power

x^-18-6 = x^-24 ➡ 1/x^24

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Sliva [168]

Answer:

80

Step-by-step explanation:

18^2 + 80^2 = 82

324 + 160 = c^2

4 0
3 years ago
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omeli [17]

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Step-by-step explanation: its good

7 0
2 years ago
The millers are going to put a pool in their backyard this summer. The pool will have a depth of 5 feet, and the dimensions show
erica [24]

Answer:

D : 510 units

Step-by-step explanation:

NOTE:

Something to consider when solving problems like this is to break the large shape down into smaller, more managable shapes. So for this problem, you can break down this irregular shape into two rectangles. This will make solving problems similar to this easier in the future :)

WORK:

I broke down this shape into two rectangles with the following dimensions:

- 12 meters by 5 meters

- 3 meters by 14 meters

You also know that the depth has to be 5 feet (the problem itself did not account for differences in feet and meters, as when I converted the 5 feet to meters and solved that way, none of the answers were correct)

Using this information, you can now solve for the volume of each of the rectangles

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510 units

3 0
2 years ago
Find the value of “x” so that a parallel to b
Kaylis [27]

Answer:

Step-by-step explanation:

3x - 50 = 2x - 5     { a// b,  so alternate interior angles are equal}

3x - 2x = -5 +50

        x = 45

8 0
3 years ago
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What equation can I use to find the side of a cube whose area is 729?
Tom [10]
#1 There is no area of a cube. There is only a volume.
#2 The formula is V = s^{3} where s is the side.

Substitute 729 in V since that is the volume.
729 = s^{3}

Take the cube root and you will get 9.

So the formula is V = s^{3} and the side is 9. 
8 0
3 years ago
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