Answer:
Step-by-step explanation:
Given
No of sample space , n(s)= 15
Even numbers = ( 2 , 4 , 6 , 8 , 10 ,12 , 14 )
No of favorable cases of getting even numbers , n(a)= 7
Now
Multiples of 3 = ( 3, 6 , 9 , 14, 15 )
No of favorable cases of multiples of 3 , n(b) = 5
Now
n ( a ∩ b)= 2
Now Probability of picking a card that is an even number or a multiple of 3
P( a U b) or
P( a or b)
= P(a) + P(b) - P( a ∩ b )
= n(a)/ n(s) + n(b) / n(s) - n( a∩ b) / n(s)
= 7 / 15 + 5 / 15 - 2/15
= ( 7 + 5 - 2) / 15
= 10 / 15
= 2 / 3
Hope it helps :)
