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Illusion [34]
3 years ago
13

Find the coordinates of the midpoint of the segment joining the given points of (0,2) and (6,4)

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad(\stackrel{x_2}{6}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{6+0}{2}~~,~~\cfrac{4+2}{2} \right)\implies (3~,~3)

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3 years ago
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Given: ABCD trapezoid<br> BC=1.2m, AD=1.8m<br> AB=1.5m, CD=1.2m<br> AB∩CD=K<br> Find: BK and CK
stepladder [879]

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

AD\parallelBC

\angle KBC=\angle KAD              (Corresponding angles)

\angle KCB=\angle KDA             (Corresponding angles)

By AA rule of similarity

\triangle KBC\sim \triangle KAD

Corresponding sides of similar triangles are proportional.

\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}

\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{1.2}{1.8}

\frac{x}{x+1.5}=\frac{2}{3}

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x=3

The length of BK is 3 m.

\frac{y}{y+1.2}=\frac{1.2}{1.8}

\frac{y}{y+1.2}=\frac{2}{3}

3y=2y+2.4

y=2.4

The length of CK is 2.4 m.

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