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Ne4ueva [31]
1 year ago
9

Find the sum of the following geometric sequences. d) 3 terms a= 16 r=3/4​

Mathematics
1 answer:
kodGreya [7K]1 year ago
7 0

Answer:

S₃ = 37

Step-by-step explanation:

given a₁ = 16 and r = \frac{3}{4} , then

a₂ = a₁ × \frac{3}{4} = 16 × \frac{3}{4} = 12

a₃ = a₂ × \frac{3}{4} = 12 × \frac{3}{4} = 9

then

S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37

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2 years ago
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