Question

Let f(x)=x-3 and g(x)= x^2 find f(g(4))

Answer 1

Answer:

the value of $f(g(4))$ is, 13

Step-by-step explanation:

Given the function:

$f(x) = x-3$

$g(x) = x^2$

we have to find the value of $f(g(4))$;

$f(g(x)) = f(x^2)$

Replace x in place of $x^2$ in the fucntion f(x) we have;

$f(g(x)) =f(x^2) = x^2-3$

⇒$f(g(x)) = x^2-3$

Put x = 4 we have;

$f(g(4)) = 4^2-3=16-3 =13$

Therefore, the value of $f(g(4))$ is, 13

Answer 2

Answer: 13 your welcome boo lol