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il63 [147K]
3 years ago
11

I am having trouble. Help plz

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0
Area is calculated by multiplying length by width.  Since we are given the width, we can test each length and see if the product matches the rectangle's area.

(2m - 3)(4m - 4)  =  8m² - 20m + 12  ≠  8m² + 4m - 12

(8m - 3)(4m - 4)  =  32m² - 44m + 12  ≠  8m² + 4m - 12

(2m + 3)(4m - 4)  =  8m² + 4m - 12

(8m + 3)(4m - 4) =  32m² + 20m - 12  ≠  8m² + 4m - 12

The length of the rectangle must be 2m + 3.  Another method of solving this would be to divide the area by the width, or 8m² + 4m - 12  ÷  4m - 4.
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What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6
vodka [1.7K]

Answer:

(x+1) is a factor with remainder 0.

Step-by-step explanation:

We divide (x+1) into the polynomial -3x^4+2x^3-x^2+6 through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial -3x^4+2x^3-x^2+6 .

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This leaves 5x^3-x^2+6. We repeat the step above.

(x+1)(5x^2)=5x^3+5x^2.

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(x+1)(-6x)=-6x^2-6x.

We subtract this from -6x^2-(-6x^2)+0x-(-6x)+6=6x+6. We repeat the step above.

(x+1)(6)=-6x+1.

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Number one and two please?
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