I need help doing what’s in the pictureee plz help I need help like NOW
1 answer:
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Answer: p > 5
Step-by-step explanation: screenshot
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
So we just need to plug in our values and solve
we are given v is 369 so we have
now we solve for x.
divide both sides by 20
square both sides
subtract 273 from both sides
so a temp of about 67 degrees C
we are given v is 369 so we have
now we solve for x.
divide both sides by 20
square both sides
subtract 273 from both sides
so a temp of about 67 degrees C