U = ( -8 , -8) v = (-1 , 2 ) <span>the magnitude of vector projection of u onto v = </span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll </span> <span>ll v ll = √(-1² + 2²) = √5 </span> u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8 ∴ <span>(u . v )/ ll v ll = -8/√5</span> ∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll] </span> <span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 ) </span> The other orthogonal component = u - ( 8/5 , -16/5 ) = (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 ) </span> So, u <span>as a sum of two orthogonal vectors will be </span> u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
You have to make a tape diagram and divide it in to 9 parts because it is 5 out of 9 then you will make a bracket pointing to only 4 parts of the tape diagram then you do 36/9 and it will equal 4 so put 4 in to each part and so 4 x 4 is 16 so the answer is 16 people prefer historical books
if you want to find another position other than 1/6 like 4/6 then you can just times the answer in this case 30 by the amout u need in this case 4 so 4/6 would be 120 which is 2 hours
