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defon
3 years ago
7

Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v

Mathematics
2 answers:
il63 [147K]3 years ago
5 0

Answer:

<h2>all I can say is that it's NOT C (-1,2)+(-2,-1)</h2>

Step-by-step explanation:

blagie [28]3 years ago
3 0
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8 
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span>                          = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
                                   = (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>










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...... Plz look at the picture and answer it.....
AURORKA [14]

Answer:

B. 3.99x10^-6

Step-by-step explanation:


7 0
4 years ago
An 18 in long rebar is driven into the ground until it touches an underground pipe. A backsight to a benchmark with an elevation
WARRIOR [948]

Answer:

398.71 ft

Step-by-step explanation:

Length of rebar = 18 inches  = 1.5 ft

Elevation  = 393.66 ft

Reading of backsight on Benchmark= 7.56 ft

Rod reading = 1.10 ft

<em>First step : determine height of Instrument been used</em>

= elevation + backsight on Benchmark

= 393.66 + 7.56 = 401.22 ft

<em>Elevation of top of rebar </em>

= 401.22  - 1.01  = 400.21 ft

Finally determine the elevation of the top of the pipe

= 400.21 - length of Bar

= 400.21 - 1.5 = 398.71 ft

6 0
3 years ago
I need a lot of help with this question!!!!!!<br><br>CLICK THE PICTURE
malfutka [58]
I need a lot of help with this question!!!!!!

CLICK THE PICTURE


The x is going to =7.5 i belive is right
8 0
3 years ago
The first part of a trip driving at 40 mph was 15 miles longer and took 30 minutes longer than the second part of the trip drivi
kenny6666 [7]

Answer:

65 miles

Step-by-step explanation:

There are two simultaneous equations . Remeber that v=d/t, 1hour = 60 minutes.

1. 40 = (d+15)/(t+0.5)

2. 50 = d/t

solving: d= 25 miles and t=0.5 hours.

The distance traveled is:

D=d+d+15

D=65 miles

5 0
3 years ago
Read 2 more answers
Help someone please!! Ty
erma4kov [3.2K]

Answer:

Option (B)

Step-by-step explanation:

Let the five distinct positive integers are a, b, c, d, e.

Average of these five integers is 20.

\frac{a+b+c+d+e}{5}=20

a + b + c + d + e = 100

If these integers are in the increasing order,

Median of these integers 'c' = 12

If the sum of d and e is the largest then the sum of a and b will be the smallest.

Therefore, the smallest positive integers a and b will be,

a = 1 and b = 2

1 + 2 + 12 + d + e = 100

15 + d + e = 100

d + e = 100 - 15

d + e = 85

Since d will be greater than the median c,

d > c

d > 12

For the largest value of integer 'e', value of 'd' will be minimum.

The least value of d will be = 13

Then, 13 + e = 85

e = 85 - 13

e = 72

{a, b, c, d, e} = {1, 2, 12, 13, 72}

Therefore, the largest possible number is this set will be 72.

Option (B) will be the answer.

5 0
3 years ago
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