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Stella [2.4K]
3 years ago
6

Choose an object that is about the same length as a baseball bat. Explain how to estimate its length in feet.

Mathematics
1 answer:
Ronch [10]3 years ago
8 0
A log. You estimate it's length in feet by measuring the longest side.
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This graph relates the volumes of triangular pyramids with a base area of 12 square inches and their heights.
Nikolay [14]

Answer:

V=40\ in^3

Step-by-step explanation:

The graph is not attached, however we know that, the volume of a triangular pyramid is given by the formula

V=\frac{1}{3}Bh

where

B is the area of the triangular face

h is the height of the pyramid

we have

B=12\ in^2\\h=10\ in

substitute the given values

V=\frac{1}{3}(12)(10)=40\ in^3

3 0
4 years ago
In how many years will Rs.1200 at the rate of 15% interest amount to Rs. 1740​
Anvisha [2.4K]

Find the interest amount.

I=1740-1200=540

Use the formula for simple interest.

I=prt/100

Solve for t.

540=1200 \times 15\% \times t

540=1200 \times \frac{15}{100}  \times t

540=180t

t=\frac{540}{180}

t=3

<h2>3 years.</h2>
6 0
3 years ago
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I don’t understand this problem
Wittaler [7]

68x87 i think?

sorry if that isnt right..

3 0
3 years ago
Read 2 more answers
How many solutions are there to this equation?<br> 6x+15=6(x-3)
nadya68 [22]
There is approximately 1 solution for this equation
4 0
4 years ago
William and Stephanie are playing a rather dangerous game of catch on the rooftops of skyscrapers in downtown Chicago. William i
olasank [31]
The question involves the concept & equations associated with projectile motion.

Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²


Of the possible equations of motion, the one we'll find useful is:

y₂ = y₁ + v₁t + 1/2gt²

We can just plug and chug to define the equation of motion:

<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>


<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>

7 0
4 years ago
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