Step-by-step explanation:
-7(1+3x) = 4 + 5x
-7 - 21x = 4 + 5x
(get all the variables on one side. Don't forget to change the signs)
-7-4 = 5x + 21x
-11 = 26x
(divide both sides by the coefficient [26])
26x/26= -11/26
x = -11/26
The answer for that would be 6x^2 + 8x 13.
P(J / R) = P (J and R) / P(R)
<span>0.8 = P (J and R) / 0.6 </span>
<span>P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] </span>
<span>P(J / NR) = P (J and NR) / P(NR) </span>
<span>0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 </span>
<span>P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] </span>
<span>Hence; </span>
<span>Propability of John practicing regardless of weather condition is </span>
<span>P(John Practicing) = 0.48 + 0.16 = 0.64</span>
The answer would be - B. All real numbers
Answer:
I hope this helps :D
Step-by-step explanation:
4
It can be done a lot easier: instead of calculating the probability of one head, two heads, three heads, ... one just needs to calculate the probability of no heads: that is simply 0.5
0.5
n
. If you subtract it from 1, you get the probability you want: it's because that's the chance of not no heads, meaning at least one head. So, the formula is: 1−0.5
1
−
0.5
n
More formally: if X is throwing at least one head,
()=1−(¬)
P
(
X
)
=
1
−
P
(
¬
X
)
, where ¬
¬
X
is throwing zero heads.
