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Maslowich
3 years ago
15

1.05555555556 as a fraction

Mathematics
2 answers:
strojnjashka [21]3 years ago
4 0
That number as a fraction is 19/18
kherson [118]3 years ago
4 0
As topheavy: 19/18
Or as a mixed number: 1 1/18
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A 1.50 liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25oC. Without change in t
cricket20 [7]
The answer is 4.5 l

To calculate this, we will use the Boyle's law using constant k, pressure P, and volume V:

 PV = k

We can forget temperature since it is constant.

We have:

P1V1 = k

P2V2 = k

So, P1V1 = P2V2

P1 = 3 atm

V1 = 1.5 l

P2 = 1 atm

V2 = ?

_____

P1V1 = P2V2

3 atm * 1.5 l = 1 atm * V2

4.5 atm/l = 1 atm * V2

V2 = 4.5 atm l / 1 atm

V2 = 4.5 l

5 0
3 years ago
Read 2 more answers
In a recent survey of college professors, it was found that the average amount of money spent on entertainment each week was nor
Alenkinab [10]

Answer:

0.0918

Step-by-step explanation:

We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The mean and standard deviation of average spending of sample size 25 are

μxbar=μ=95.25

σxbar=σ/√n=27.32/√25=27.32/5=5.464.

So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.

The z-score associated with average spending $102.5

Z=[Xbar-μxbar]/σxbar

Z=[102.5-95.25]/5.464

Z=7.25/5.464

Z=1.3269=1.33

We have to find P(Xbar>102.5).

P(Xbar>102.5)=P(Z>1.33)

P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)

P(Xbar>102.5)=0.5-0.4082

P(Xbar>102.5)=0.0918.

Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.

5 0
3 years ago
Amelia needs to buy some cat food. At the nearest​ store, 2 bags of cat food cost $4.50. How much would Amelia spend on 6 bags o
marissa [1.9K]

Answer:

$13.50

Step-by-step explanation:

<u><em>2 bags of cat food = $4.50</em></u>

<u><em>1 bag of cat food = 2/4.50</em></u>

<u><em>= 2.25</em></u>

<u><em>6 bags of cat food = 2.25*6</em></u>

<u><em>=13.50</em></u>

7 0
3 years ago
Read 2 more answers
Express the ratio as a decimal. Round to the nearest hundredth.
Andru [333]

Answer:

What ratio, and give me more details and I will come back and edit my answer.

Step-by-step explanation:

6 0
4 years ago
Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

Given that,

Amount earned by Joe = $ 14 per hour

Amount earned by Blaine = $ 18 per hour

Lets assume the number of six month intervals be "x"

<em><u>Joe receives a raise of $1.75 every six months</u></em>

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

14+1.75x = 18+0.75x\\\\1.75x-0.75x = 18-14\\\\1x = 4\\\\x = 4

Thus after 4 interval of six months, Joe to earn same hourly rate as Blaine.

8 0
4 years ago
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