All categories

3 years ago

What is the equation of a line the passes through the point (-1,3) and has a slope of -3?

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

Answer:

Given points ( -1 ,3 ) and slope(m) = -3

Step-by-step explanation:

The equation of a line is given by 

y - y1 = m ( x - x1 )

y - 3 = -3 ( x +1 )

y - 3 = -3x - 3

3x + y -3 +3 =0

3x + y = 0

which is the required equation 

You might be interested in

If the cost of 819.73 for full cover insurance for a female and a male is 1192.64 what is the percentage?

irinina [24]

Answer:

68.7%

Step-by-step explanation:

If the cost of 819.73 for full cover insurance for a female and a male is 1192.64 what is the percentage?

The Percentage is calculated as:

819.73/1192.64 × 100

= 0.68732392004293 × 100

= 68.732392004 %

Approximately = 68.7%

Therefore, the percentage is 68.7%

7 0

3 years ago

What are the domain restrictions of the expression?

lubasha [3.4K]

h^2 - 12h + 20 can be factored to:

(h-10)(h-2)

These cannot be zero so, h cannot be 10 or 2.

7 0

3 years ago

Read 2 more answers

Choose the value of x that makes the open sentence true 40-x^2 < 2x+15.

S_A_V [24]

I believe the answer is B, but I'm not 100% sure. :)

6 0

3 years ago

Read 2 more answers

—330 + 450 need help !!!!!!!

natta225 [31]

120
hope that helps

7 0

3 years ago

Read 2 more answers

Question 5 (1 point)

riadik2000 [5.3K]

Answer:

The area of sector AOB is 75.36 unit²

Step-by-step explanation:

Consider the provided information.

Circle O with minor arc AB=60 degrees and OA =12.

We need to find the area of sector.

Area of the sector: $A=\frac{\theta }{360} \times \pi r^2$

Substitute $\theta=60$ and r =12 in above formula.

$A=\frac{60}{360} \times 3.14\times (12)^2$

$=\frac{1}{6} \times 3.14\times 144$

$=24\times 3.14$

$=75.36$

Hence, the area of sector AOB is 75.36 unit²

8 0

3 years ago