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4 years ago

Drag the tiles to the correct boxes to complete the pairs. Kevin has diabetes -

Mathematics

2 answers:

sashaice [31]4 years ago

7 0

1) The probability that Kevin has diabetes and the test predicts opposite to be true = Probability Kevin has diabetes x Probability that test predicts opposite to be true.

Probability that Kevin has diabetes = 0.75
Probability that test predicts opposite to be true (i.e test predicts he doesn't have diabetes) = 0.15

So,
The probability that Kevin has diabetes and the test predicts opposite to be true = 0.75 x 0.15 = 0.1125

2) The probability that Kevin does not have diabetes and the test predicts this correctly = Probability Kevin does not diabetes x Probability that test predicts this correctly.

Probability that Kevin does not have diabetes = 0.25
Probability that test predicts this correctly (i.e. test predicts he does not have diabetes) = 0.85

So,
The probability that Kevin does not have diabetes and the test predicts this correctly = 0.25 x 0.85 = 0.2125

3) The probability that Kevin does not have diabetes and the test predicts the has diabetes = Probability Kevin does not diabetes x Probability that test predicts he has diabetes.

Probability that Kevin does not have diabetes = 0.25
Probability that test predicts has has diabetes = 0.15

So,
The probability that Kevin does not have diabetes and the test predicts the has diabetes = 0.25 x 0.15 = 0.0375

Leviafan [203]4 years ago

6 0

Answer:

Kevin has diabetes and the test predicts this = .6375

Step-by-step explanation:

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Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

Range: (2,∞+)

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

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