Answer:
The correct answers would be maintain chromosome number through generations and cause genetic variations by recombination.
In Meiosis a cell divides into four daughter cells all of which have half the number of chromosomes present in a parent cell.
It helps in the formation of gametes in sexually reproducing organisms.
These gametes (one from father and one from mother) fuse together to form a zygote. It re-established the chromosomal number as that of the parent.
In absence of meiosis, the chromosomal number would have doubled after each generation.
In addition, the meiosis also increases the genetic variation among the population with the help of crossing over which occurs during the pachytene stage of prophase I.
During this event, genetic information is exchanged between the non-sister chromatids of the homologous chromosomes. It produces a new combinations of genes that are different from either parent.
Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
if its BB or Bb the offspring will show the dominant trait
Explanation:
If its bb then the trait wont be expressed
