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Mariana [72]
3 years ago
14

A chord of a circle is a line segment connecting any point on the circle to the center of the circle.

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

  FALSE

Step-by-step explanation:

A chord of a circle is a line segment that connects two points on the circle.

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Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo
ehidna [41]

a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3


b=11011000 =  11011_2 \times 2^{000_2} = -(0100_2 + 1) =-(4+1)=-5


a+b=-2 = -1 \times 2^{001} = -2 \times 2^{0} = -4 \times 2^{-1} etc.


a+b=-2 = 11111001 = 11110000 = 11100111 = ...


Hard to select the correct answers without seeing the choices. Let's check a couple,


11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark


11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark


11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark


4 0
3 years ago
Given that f(x)=x2-1 and g(x)=2x+8 find (g-f)(10)
irga5000 [103]

Answer:

<h2>(g-f)(10) = - 71</h2>

Step-by-step explanation:

f(x) = x² - 1

g(x) = 2x + 8

To find (g-f)(10) first find ( g - f)(x)

To find ( g - f)(x) subtract f(x) from g(x)

That's

( g - f)(x) = 2x + 8 - ( x² - 1)

Remove the bracket

( g - f)(x) = 2x + 8 - x² + 1

Simplify

( g - f)(x) = - x² + 2x + 9

To find (g-f)(10) substitute the value in the bracket that's 10 into ( g - f)(x)

That is

(g-f)(10) = -(10)² + 2(10) + 9

= - 100 + 20 + 9

= - 100 + 29

= - 71

Hope this helps you

7 0
3 years ago
Please help me! I have no idea how to do this
elena-s [515]

The best way to do this is to make up values for the sides.

Say the lengths of square B's sides are each 4 cm. That means A's sides are 2 cm.

So, the area of square B is 4^2 = 16 cm^2, and A's area is 4 cm^2. We can see the shaded area is half of A, so it's 2 cm^2.

What percent of 16 is 2?

2 / 16 * 100 = 12.5%

5 0
3 years ago
Can someone help me with these geometry questions? I can’t seem to understand them. If u find the answers, can u explain it too?
rusak2 [61]

<em>Question 5</em>

Vertical angles are <u>congruent</u>. Therefore, 3y=\boxed{150}. The sum of two supplementary angles equals \boxed{180^{\circ}}.

Therefore, 6x+150=\boxed{180}

<em>Question 6</em>

\angle b-14=90-\angle b\\\\2\angle b=104\\\\\angle b=\boxed{52^{\circ}}

<em>Question 7</em>

<em />\angle d+32=180-\angle d\\\\2\angle d=146\\\\\angle d=\boxed{73^{\circ}}

<em>Question 8</em>

<em />7x-80=3x\\\\-80=-4x\\\\x=20\\\\\implies \boxed{m\angle 1=m\angle 3=60^{\circ}}

6 0
1 year ago
$35,125 loan, a feat which took ten years of quarterly payments. The loan had an interest rate of 7.44%, compounded quarterly. I
Darya [45]
First find the amount of each payment:
35,125 = P(\frac{(1+i)^{40} -1}{i (1+i)^{40}}) , i = \frac{.0744}{4}  \\  \\ P = 1252.70

The total cost will be 40 payments plus service charges.
40*1252.70 + 5180.70 = 55,288.90

The percentage is the service charge divided by total cost:
X = \frac{5180.70}{ 55,288.90} = .0937 = 9.37\%
7 0
3 years ago
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