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sergejj [24]
3 years ago
13

Find quotient (2x-3/x) / (7/x^2)

Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:

2x^3-3x/7

I hope it's helpful

You might be interested in
Write 0.216 as a rational number in lowest terms
lozanna [386]

Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

=\frac{0.216\cdot \:1000}{1000}

=\frac{216}{1000}

216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

6 0
3 years ago
Please help will mark brainliest.
olasank [31]

Answer:

(g)x divided by 12/4

Step-by-step explanation:

6 0
3 years ago
I need to know how to make it in its simplest form
Mrrafil [7]
Multiply denominator by whole number then add that number to the nominator. Which would be 5 times 1 plus 3. SO 5+3 IS 8 and you keep the denominator so the first one is 8/5
6 0
3 years ago
Which triangle side lengths form a right triangle? Choose all that apply.
dybincka [34]
C. 8,15,17
E. 15,20,25
4 0
3 years ago
There are 5 jars of jelly beans on a table. Each jar contains 39,781 jelly beans. How many jelly beans are there in all?
alexira [117]
39781 x 5 = 198905
There are 198905 jelly beans in total:)
5 0
3 years ago
Read 2 more answers
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