Solve the following equation. log(3x)=log(2x-4) *

Mathematics

1 answer:

Irina18 [472]2 years ago

5 0

log(3x) = log(2x-4)

taking antilog of both sides:

3x = 2x - 4

3x - 2x = -4 [subtracting 2x from both sides]

x = -4

and we're done already!

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