You take 3•4 to get 12, then you add a zero to that and get 120. You then multiply by six and get 720.
The equation of the line is y = 1/6x + 3
<h3>How to determine the equation?</h3>
The equation of the line is given as:
y = -6x - 14
The above equation has a slope of
m = -6
Let the slope of the other line be n.
So, we have:
n =-1/m ---- slope condition for perpendicular lines
So, we have:
n = 1/6
The equation is then calculated as:
y = n(x - x1) + y1
Where
(x1, y1) = (12,5)
This gives
y = 1/6(x - 12) + 5
Expand
y = 1/6x - 2 + 5
Evaluate the sum
y = 1/6x + 3
Hence, the equation of the line is y = 1/6x + 3
Read more about linear equations at:
brainly.com/question/14323743
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Step-by-step explanation:
well, the starting equation and the target format have been given.
let's do the multiplications and compare the target with the starting information.
from there we see what is different or missing.
x² + 14x + 13 = 0
and
(x - p)² = q
x² - 2px + p² = q
x² - 2px + (p² - q) = 0
now let's compare the different parts :
x² = x²
-2px = 14x
-2p = 14
p = -7
p² - q = 13
-7² - q = 13
49 - q = 13
36 - q = 0
q = 36
so, the square (x - p)² = (x + 7)² is completed when
x² + 14x + 49 = 0
but we have only "+ 13". so we need to add 36 to get 49. but we need to do it on both sides, to keep the equation true :
x² + 14x + 13 + 36 = 36
x² + 14x + 49 = 36
(x + 7)² = 36
just as we calculated already above.
and now this can be solved by pulling the square root on both sides (a quadratic equation has always 2 solutions)
x + 7 = ±6
x1 = 6 - 7 = -1
x2 = -6 - 7 = -13
