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3 years ago

Solve for the unknown value

Mathematics

1 answer:

Oksanka [162]3 years ago

3 0

Answer:

There is nothing included so I can't give you an answer.

Step-by-step explanation:

You didn't add anything to this. All it says is "Solve for the Unknown Value". I would help you if I could though!

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3 years ago

You deposit $7,900 in an account that pays 1.29% annual interest. Find the balance after 5 years when theinterest is compounded

hjlf

Answer:

8,425.47

Step-by-step explanation:

Total Principal: $7,900.00

Total Interest: $525.47

interest rate of 1.29% compound quarterly is equivalent to annual rate of 1.296%

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3 years ago

Which numbers are perfect squares

dimaraw [331]

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4 years ago

(1 point) Consider the function f(x)=2x3−9x2−60x+1 on the interval [−4,9]. Find the average or mean slope of the function on thi

OlgaM077 [116]

Answer: c = 4.97 and c = -1.97

Step-by-step explanation: <u>Mean Value Theorem</u> states if a function f(x) is continuous on interval [a,b] and differentiable on (a,b), there is at least one value c in the interval (a<c<b) such that:

$f'(c) = \frac{f(b)-f(a)}{b-a}$

So, for the function f(x) = $2x^{3}-9x^{2}-60x+1$ on interval [-4,9]

$f'(x) = 6x^{2}-18x-60$

f(-4) = $2.(-4)^{3}-9.(-4)^{2}-60.(-4)+1$

f(-4) = 113

f(9) = $2.(9)^{3}-9.(9)^{2}-60.(9)+1$

f(9) = 100

Calculating average:

$6c^{2}-18c-60 = \frac{100-113}{9-(-4)}$

$6c^{2}-18c-60 = -1$

$6c^{2}-18c-59 = 0$

Resolving through Bhaskara:

c = $\frac{18+\sqrt{1740} }{12}$

c = $\frac{18+41.71 }{12}$ = 4.97

c = $\frac{18-41.71 }{12}$ = -1.97

<u>Both values of c exist inside the interval [-4,9], so both values are mean slope: c = 4.97 and c = -1.97</u>

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4 years ago

If x^2=40, what is the value of x?

Ainat [17]

if x^2=40 you would need to square root both sides to get x alone therefore x=6.3

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3 years ago

Read 2 more answers