The Tangent Line Problem 1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
The power symbols are missing.
I can infere that the product intended to simplify is (7^8) * (7^-4)., because that permits you to use the rule of the product of powers with the same base.
That rule is that the product of two powers with the same base is the base raised to the sum of the powers is:
(A^m) * (A^n) = A^ (m+n)
=>(7^8) * (7^-4) = 7^ [8 + (- 4) ] = 7^ [8 - 4] = 7^4, which is the option 3 if the powers are placed correctly.
Answer:
-3x+16
Step-by-step explanation:
Answer:
Step-by-step explanation:
Okay!
A graph representing the function :
f(x)=x(x+2)
I will describe the graph for you!
the points on this graph are : (-3,3),(-2,0),(-1,-1),(0,0),(1,3)
the graph also creates a U shape!
7844=7400(1+(8/12)r)
Solve for r
R=0.09*100=9%
