Given : - Square ABCD with side 3. E and F as midpoints.
To find : - area of EBFD
Solution : - We have, area of square ABCD = 3 x 3 = 9 units.
Thus, (ar)EBFD = ar ABCD - ar DAE - arDCF
arDAE = 1/2 x base x height
=1/2 x 1.5 x 3 ( AE is 1/2 of AB = 1.5, DA is altitude)
= 2.25
arDFC = 1/2 x base x height
= 1/2 x 1.5 x 3 (FC is 1/2 of BC, DC is altitude)
= 2.25
Thus, (ar) EBFD = arABCD - arDAE - arDCF
= 9 - 2.25 - 2.25
= 4.5 units.
Thus, area of quad EBFD is 4.5 units.
Answer:
78
Step-by-step explanation:
Muliply 300 to 26%
Answer:
48.75
Step-by-step explanation:
340/80=16 1/4
16 1/4*3=48.75
56x y = 19 plus the rounder (45x 20)
Answer:
∠B=60°
Step-by-step explanation:
In this right traingle, using angle B, you have the opposite side which is 6√102, and the adjacent side which is 6√34. Using SOHCAHTOA this invlolves TOA so tangent B = OPPOSITE/ADJACENT or tan B = 6√102/6√34. Simplifying gives tan B=√3. You can use your calculator to solve for B by taking the inverse tangent of √3 or you can use the known trig ratios from the unit circle if you have already learned that to find that angle B is 60°
