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Vlad1618 [11]
4 years ago
10

What's the square of the quantity of 18 less than x

Mathematics
1 answer:
Zigmanuir [339]4 years ago
8 0

(18 - x)^2

If (a - b)^2 then the answer is a^2 - 2ab + b^2

18^2 - 36x + x^2

The answer is x^2 - 36x + 324

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Answer this math question ASAP pls
Bas_tet [7]

Answer:

26 + 18 = 44 and 18 + 34 = 52.

Step-by-step explanation:

hopefully this helps! i don't kno if they covered this subject in school though for me.

8 0
3 years ago
The sum of the two prime numbers between 110 and 130 is
Korvikt [17]

Prime numbers are those numbers which have only two factors, 1 and the number itself . For e.g. 3,5,7,11 etc are all prime numbers.

Between 110 and 130 we have a total of two prime numbers which are 113 and 127, since both have only two factors .

And sum of 113 and 127 is

113+127= 240

So the required answer is 240 .

7 0
3 years ago
There are 325 rows of 9 chairs in the theater. There are 102 chairs in the the balcony. About how many chairs are there?
Lesechka [4]

Answer:

There are 3027 chairs

Step-by-step explanation:

There are 2925 chairs in the theater and 102 chairs in the balcony

all together are 3027

6 0
3 years ago
Read 2 more answers
Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter
Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = x coins

So we can have two inequalities.

1) Total number of coins

x+17\geq28\\  [Since minimum number of coins=28]

2) Total value of coins

10x+(25)(17)\leq505 [As 1 dime=10 cents and 1 quarter=25 cents]

10x+425\leq505

Solving inequality (1)

Subtracting both sides by 17.

x+17-17\geq28-17

∴ x\geq 11

Solving inequality (2)

Subtracting both sides by 425.

10x+425-425\leq505-425

10x\leq 80

Dividing both sides by 10.

\frac{10x}{10}\leq \frac{80}{10}

∴ x\leq 8

On combining both solutions

x\geq 11 and  x\leq 8 ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

7 0
3 years ago
5 times the sum of a number and 27 is greater than or equal to 6 times the sum of that number and 26
tester [92]
5(x+27)\geq6(x+26)\\
5x+135\geq6x+156\\
x\leq -21


5 0
3 years ago
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